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RE: PWK in Dooe from Hope stated these dimensions 26ftX18ftX13...- looks like Fibonacci equation to me-nT

I'm not familiar with the Fibonacci equation, but I don't think it's a good idea for one of the room dimensions to be an integer multiple of another room dimension. In other words, if the ceiling is 13-feet high, I don't think you want the room length to be 26-feet. These two dimensions will reinforce the same frequency having a wavelength in air of 26-feet. I believe you want each of the main room dimensions to reinforce third octaves as in the following example:

If the ceiling height is 13-feet, then the length and width would be:

Length = 10 [Log(13) + 2*Log(2)/3] = 20.64-feet

Width = 10 [Log(13) + Log(2)/3] = 16.38-feet

Consequently, if the speed of sound in air is approximately 1125-ft/s, then these room dimensions would reinforce the following frequencies, which represent third octaves.

1125/20.64 = 54.51-Hz
1125/16.38 = 68.68-Hz
1125/13.00 = 86.54-Hz

Anyway, this would be my guess. Perhaps I'm wrong!

Happy listening!
John Elison


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