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In Reply to: PWK in Dooe from Hope stated these dimensions 26ftX18ftX13...- looks like Fibonacci equation to me-nT posted by Cleantimestream on September 12, 2023 at 11:08:42:
I'm not familiar with the Fibonacci equation, but I don't think it's a good idea for one of the room dimensions to be an integer multiple of another room dimension. In other words, if the ceiling is 13-feet high, I don't think you want the room length to be 26-feet. These two dimensions will reinforce the same frequency having a wavelength in air of 26-feet. I believe you want each of the main room dimensions to reinforce third octaves as in the following example:
If the ceiling height is 13-feet, then the length and width would be:
Length = 10 [Log(13) + 2*Log(2)/3] = 20.64-feet
Width = 10 [Log(13) + Log(2)/3] = 16.38-feet
Consequently, if the speed of sound in air is approximately 1125-ft/s, then these room dimensions would reinforce the following frequencies, which represent third octaves.
1125/20.64 = 54.51-Hz
1125/16.38 = 68.68-Hz
1125/13.00 = 86.54-Hz
Anyway, this would be my guess. Perhaps I'm wrong!
Happy listening!
John Elison
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Follow Ups
- RE: PWK in Dooe from Hope stated these dimensions 26ftX18ftX13...- looks like Fibonacci equation to me-nT - John Elison 09/13/2323:51:55 09/13/23 (2)
- Also referred to as the "Golden Ratio" - E-Stat 09:49:08 09/15/23 (1)
- RE: Also referred to as the "Golden Ratio" - John Elison 10:23:02 09/15/23 (0)