In Reply to: Not so easy after all posted by Analogtheo on April 22, 2006 at 15:17:13:
I find it easier to do parallel resistors the dumb way:
1/R1 + 1/R2 = 1/RT;
1/50,000 + 1/332,000 = 1/43,455
RT = 43,455If your desired cutoff is 16 HZ, and you are doing 1/10 that value or 1.6Hz, then:
as you stated Capacitance desired = 1,000,000/(2 x 3.14 x 1.6 x 43,455) = 2.29uF.
You did just fine your way.
If you make your output resistor really huge, say 10 Meg, so that only the 50k load matters, a 2uF cap will suffice. A 1uF cap would then provide you a 3.2Hz cutoff, still pretty good, chances are you'll be satisfied with that.
Experiment. Just don't touch the pointy end of the iron while it's on.
"You can never go fast enough" James Taylor in Two Lane Blacktop
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Follow Ups
- Re: Not so easy after all - Slick 04/22/0618:42:35 04/22/06 (7)
- Re: Not so easy after all - Analogtheo 02:25:46 04/23/06 (3)
- Shouldn't Have Any Effect - Slick 20:52:45 04/23/06 (2)
- Re: Shouldn't Have Any Effect - Analogtheo 23:51:42 04/23/06 (1)
- Re: Shouldn't Have Any Effect - Slick 08:39:08 04/24/06 (0)
- The formula that's easy to use and doesn't have unnecessary arithmetic... - jeffreybehr 22:18:11 04/22/06 (2)
- Re: The formula that's easy to use and doesn't have unnecessary arithmetic... - Ron Oehlert 00:09:56 04/23/06 (1)
- Thanx(nt) - Analogtheo 02:27:55 04/23/06 (0)