In Reply to: Dynamic impedance explained posted by JLH on July 1, 2009 at 04:36:38:
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On page three it is easy to see that at full power the tube swings from 118mA down to 12.5mA. That is a change of 105.5mA with the quiescent current of 60mA. That is a current change of 176%. The average current change from the quiescent point is 52.75mA. In PSUD I set the current draw to 60mA and then do a current step of 52.75mA. I then divide the resulting voltage drop by the step current to get the dynamic impedance of the power supply. An additional point of detail is I let the power supply simulate several seconds after the current step so an over sized capacitor reservoir doesn’t hide the true impedance of the power supply.
--John,
I agree that Class A amps do NOT always have constant current draw but
I don't quite follow your reasoning here. My take on it is as follows:The quiescent current is 60mA. When "full signal" is applied, the output
current into a resistive load swings to 118mA on the positive crest and
down to 12.5mA on the negative crest. In other words, the current swings
to +58mA above quiescent and -47.5mA below quiescentIn other words, the current swing is +58 ma from quiescent on positive
half-cycles and -47.5 mA on negative half-cycles. The average current,
under full signal conditions, over the entire cycle is thus
[(118 - 12.5)/2 + 12.5] or 65.25 mA (OK so far?)So we have idle current of 60mA and full signal current of 65.25mA for
a 5.25 mA increase in average current. This is the DC current change from
zero signal to full signal. If you applied a full signal rectangular tone
burst to the amp, you would observe a square wave current on the B+ of
5.25 mA peak amplitude. I believe this is the correct value to plug into
PSUD for the current step in this case.The AC swing from 12.5 mA to 118mA must also be sourced by the B+ supply,
but even at 20 Hz the final filter cap has a pretty low impedance (50 uF
~= 160 ohms) compared to the Ri of a 2A3.It's debatable by engineering types whether a 10% current step in a class
A amplifier power supply should be audible, but all you need to do is AC
couple a similar signal onto the B+ of an amp and listen for yourself.Now I do believe that the time response to the current step is important,
and tuning the power supply to have a fast ( <20mS), near critically
damped voltage response to the signal current step might make the amp
sound more dynamic and "fast", or at least prevent the B+ from making
it sound "slow".Cheers,
Michael
PS another way to say this is that the second harmonic distortion inherent
in large signal swing operation of a class A SE amp increases current draw
from the B+ in proportion to the amount of 2F distortion added.
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Follow Ups
- RE: Dynamic impedance explained - Michael Koster 07/2/0908:54:13 07/2/09 (11)
- It’s not about averages, it about instantaneous. (nt) - JLH 12:21:50 07/2/09 (7)
- RE: It’s not about averages, it about instantaneous. (nt) - Michael Koster 12:50:01 07/2/09 (6)
- The PSUD step function - tweakydee 20:02:17 07/2/09 (3)
- RE: The PSUD step function - Michael Koster 08:11:03 07/3/09 (2)
- great, thanks! nt - tweakydee 07:10:41 07/4/09 (0)
- RE: The PSUD step function - PakProtector 09:04:50 07/3/09 (0)
- RE: It’s not about averages, it about instantaneous. (nt) - PakProtector 13:27:16 07/2/09 (1)
- RE: It’s not about averages, it about instantaneous. (nt) - tube wrangler 20:27:08 07/2/09 (0)
- Great points - Tre' 10:49:32 07/2/09 (2)
- RE: Great points - tube wrangler 20:45:50 07/2/09 (1)
- revisionist history - PakProtector 04:42:50 07/3/09 (0)