In Reply to: RE: Dynamic impedance explained posted by Tre' on July 1, 2009 at 09:23:45:
hey-Hey!!!,
The large capacitor at the end of the filter will deal with both the increasing load and the decreasing load without a large change in voltage. Small change in voltage with different current delivery equals low impedance. The rest of the PS is delivering current to the last cap under what ever DCR its components happen to have; take an additional 20% on one half of a wave, and 20% less half a cycle later and we'll see an output voltage change dependant on the large cap for the most part.
Now, it remains to be seen what sort of PS behaviour makes an amp sound best. There are claims made in favour of several general PS performances. Seems a much more useful topic; determine why certain PS behaviour is desired....
cheers,
Douglas
Friend, I would not hurt thee for the world...but thou art standing where I am about to shoot.
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Follow Ups
- RE: Dynamic impedance explained - PakProtector 07/2/0905:30:02 07/2/09 (0)