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In Reply to: Dynamic impedance explained posted by JLH on July 1, 2009 at 04:36:38:
"Your assumption that a Class A amplifier would only undergo 10% change in current is greatly under estimated. "You missed my point completely. I never said that the current draw change in my amplifier was limited to 10%.
Of course there is more than a 10% current draw change. But measuring the voltage change for a given current change still gives the impedance of the supply. I chose to use a current change that happened to equal 10% of idle. The fact that I chose 10% is not relevant.
"For the most part it is impossible to drain a large capacitor reservoir in 50ms (a full wave at 20Hz). "
The 20Hz wave will only cause an increase (over idle) in current draw for the first 1/4 wave. The next 1/4 wave returns the current draw back to idle and the next 1/4 wave reduces the current draw from idle to less than idle and the last 1/4 wave returns the current draw to idle.
So why are you talking about 50ms?
"An additional point of detail is I let the power supply simulate several seconds after the current step so an over sized capacitor reservoir doesn’t hide the true impedance of the power supply."
Why? The true impedance of the supply (under the conditions we are using it) would be shown IF the simulator showed a slow (following the music) increase in current draw change followed by a slow DECREASE in current draw, not a sudden and long lived change.
Tre'
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Follow Ups
- RE: Dynamic impedance explained - Tre' 07/1/0909:23:45 07/1/09 (1)
- RE: Dynamic impedance explained - PakProtector 05:30:02 07/2/09 (0)
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