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Is it this simple?

Won't the RMS voltage at one anode times the average DC current through the cathode resistor (minus screen current) for that tube equal 1/2 the power being delivered to the transformer? Or will power factor or other issues get in the way of this simple measurement? There's not much phase shift through the transformer at these frequencies, so I wouldn't think its reactance would create a problem.

EDIT: The current measurement would need to be AC signal current, not average DC. In fact, it might be necessary to insert a low-value resistor in series with the anode temporarily and calculate anode current by measuring the AC voltage drop across that. Otherwise, signal current into the screen would skew the result.




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  • Is it this simple? - Triode_Kingdom 09/17/2114:41:01 09/17/21 (1)
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