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In Reply to: Re: PP amplifier measured data posted by mqracing on September 29, 2004 at 18:44:45:
"By the same token, if one measures current by measuring voltage drop across a resistor they must understand that they aren't measuring RMS current but measuring peak AC current."Say what? I = E/R. Fundamental rule. If the resistor is purely resistive, than the voltage across it will be representitive of the current through it. I think what is meant here is a reference to the fact that meters (DMM, VOM, etc) react differntly to complex waveforms. Hence the term 'TRUE RMS'. Commonly, the 'voltmeter' reacts to the peak to peak voltage, and converts the measurement to RMS assuming a sine wave signal. More expensive "TRUE RMS" voltmeters have various means to correct for complex, non sinusoidal waveforms.
P.S. As much as I respect Steve Bench, he could be wrong. Take a look at the measured data.
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Follow Ups
- I = E/R - mikeyb 09/30/0406:03:47 09/30/04 (2)
- For AC that's I=E/Z - Russ57 10:41:45 09/30/04 (1)
- Re: For AC that's I=E/Z - Steve O 19:02:46 09/30/04 (0)
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