In Reply to: Re: IM is the elephant... posted by mfc on July 26, 2003 at 15:21:35:
Most of the IM turns out to be from a slight overload problem.I analyzed the frequency graph in terms of what each component meant.
Here is a breakdown from 13F1 to 3F2.
F1=1050Hz square wave (out to 27th harmonic)
F2=5Khz sine waveDescription Product > 250uV <250uV
------------ ------- ---------------
Input Signal 13F1...13650
...............4F2-6F1................13700
...............18F1-F2...13900
................3F2-F1................13950
..............23F1-2F2...14150
...............2F2+4F1...14200
..............28F1-3F2...14400
................F2+9F1....14450
..............33F1-4F2................14650
14th Harmonic 14F1..14700
...............4F2-5F1................14750
...............19F1-F2...14950
3rd Harmonic 3F2....15000
When you zoom in on the bottom of the waveform in the time domain,
at the very tip where the Gibbs is the most pronounced. That is the
fastest transition area. That peak of the Gibbs (at the bottom) is
actually rounded off compared to the otherside (top) of the waveform.
This is only happening on the bottom of the waveform and only in the
uncompensated case.It appears that in the uncompensated case, the Gibbs area of the
waveform is boosted by the peak in frequency response. This puts the
negative peak over the edge as far as clipping goes. That seems to be
generating all the IM components.These don't appear to be influencing the harmonics of the little sine
wave. I'm going to go back and check.
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Follow Ups
- Re: IM is the elephant... - mfc 07/29/0318:05:20 07/29/03 (0)