In Reply to: Re: test for transients posted by john curl on July 15, 2003 at 10:03:44:
First of all, much of the IM distortion produced by a square wave will fall back on the square wave harmonics.But the second order IM products (i.e. f 1 + f 2 , f 2 - f 1 ) which are typically the dominant products will all be even and fall between the square wave harmonics.
A real world perfectly symmetrical square wave is rare, and I had to add a trim pot to my Heathkit square wave generator in order to make it so. Of course, by computer generating the square wave, you can do really well.
He'll be doing this in simulation so it's not a problem.
Still, the odd order harmonics will fold back on the primary signal.
The third order IM products (i.e. 2f 1 + f 2 , 2f 2 + f 1 , 2f 2 - f 1 , 2f 1 - f 2 ) will. But that's why he's planning to use a subtractive process and look at the residual.
se
"Of course that's just my opinion. I could be wrong."
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Follow Ups
- Re: test for transients - Steve Eddy 07/15/0310:53:03 07/15/03 (7)
- Re: test for transients - john curl 12:10:28 07/15/03 (6)
- Re: test for transients - john curl 12:12:18 07/15/03 (5)
- Re: test for transients - Steve Eddy 12:15:50 07/15/03 (4)
- Re: test for transients - Dan Banquer 12:21:10 07/15/03 (3)
- Re: test for transients - Steve Eddy 12:28:41 07/15/03 (2)
- Re: test for transients - Dan Banquer 12:33:33 07/15/03 (1)
- Re: test for transients - Steve Eddy 12:51:14 07/15/03 (0)