In Reply to: you'll get an estimate of sensitivity, not efficieny with such data posted by mhardy6647 on September 28, 2018 at 14:35:51:
You can only measure sensitivity, not efficiency, and you can't get an accurate result indoors, as the result is influenced by the room. You also can't read power with a meter, you can only read volts. Volts may be used to calculate power into a load, but only at one frequency at a time, and you must know the actual impedance at that frequency.
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Follow Ups
- RE: you'll get an estimate of sensitivity, not efficieny with such data - Bill Fitzmaurice 09/28/1814:42:09 09/28/18 (10)
- RE: you'll get an estimate of sensitivity, not efficieny with such data - Scott L 04:03:40 09/30/18 (4)
- RE: you'll get an estimate of sensitivity, not efficieny with such data - Bill Fitzmaurice 06:25:24 09/30/18 (2)
- RE: you'll get an estimate of sensitivity, not efficieny with such data - Scott L 07:42:17 09/30/18 (1)
- RE: you'll get an estimate of sensitivity, not efficieny with such data - Bill Fitzmaurice 08:07:37 09/30/18 (0)
- "there's no replacement for displacement" - mhardy6647 05:23:24 09/30/18 (0)
- RE: you'll get an estimate of sensitivity, not efficieny with such data - Scott L 15:20:50 09/28/18 (0)
- I assume he's using a single frequency from a signal generator - mhardy6647 14:48:08 09/28/18 (0)
- RE: you'll get an estimate of sensitivity, not efficieny with such data - Scott L 14:47:55 09/28/18 (2)
- RE: you'll get an estimate of sensitivity, not efficieny with such data - Paul Joppa 01:38:41 09/29/18 (0)
- RE: you'll get an estimate of sensitivity, not efficieny with such data - Bill Fitzmaurice 15:20:41 09/28/18 (0)