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Planar Speaker Asylum Welcome! Need support, you got it. Or share your ideas and experiences. |
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In Reply to: RE: "If we replaced the wire with foil that had 1/4th the mass and 4X the resistance per inch" ... posted by IEaudiodude on June 26, 2011 at 15:06:38:
Actually, I ran out of time and was pulled away but I suspected that there was an error, because when I calculated what the replacement of the MG12 bass/mid wire would be, with the same length and resistance, I think that I should have gotten foil dimensions that gave the same cross-sectional area as the original wire. But I didn't get anywhere even close. I figured I'd go back and fix it so I put the disclaimer in.
I have since discovered that I measured the MG12's mid/bass wire diameter incorrectly. I guess I happened to place my micrometer on one of the double-run wire pairs with a little exta glue, instead of on a single wire, and got .05 inch. I went back and measured the single wire stub that was protruding from the bottom connector and got .022 inch, which is probably .0226 inch, i.e. 23 AWG wire.
I corrected everything that referenced that wire size and then extended the post to include the calculations needed for changing an MG-12/QR's mid/bass panel into two wired-in-parallel foil panels of 8 Ohms each, per my previous post about that. It ended up having only 17.8% as much conductor mass as the original.
I'll have to give a little more thought to what effect that might have on the power requirements. The same voltage would now give only half the current. But half as much current would still accelerate the membrane up to 2.8X as much (neglecting the mass of the mylar) as the full current did with the original wire.
Cheers,
Tom
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Follow Ups
- RE: "If we replaced the wire with foil that had 1/4th the mass and 4X the resistance per inch" ... - tom_gootee 06/26/1119:28:41 06/26/11 (0)
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